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![real analysis - On the proof of sequentially compact subset of $\mathbb R$ is compact - Mathematics Stack Exchange real analysis - On the proof of sequentially compact subset of $\mathbb R$ is compact - Mathematics Stack Exchange](https://i.stack.imgur.com/UfTsz.jpg)
real analysis - On the proof of sequentially compact subset of $\mathbb R$ is compact - Mathematics Stack Exchange
![Let $A$ be a closed and bounded subset of $\mathbb{R}$ with the standard (order) topology. Then $A$ is a compact subset of $\mathbb{R}$. - Mathematics Stack Exchange Let $A$ be a closed and bounded subset of $\mathbb{R}$ with the standard (order) topology. Then $A$ is a compact subset of $\mathbb{R}$. - Mathematics Stack Exchange](https://i.stack.imgur.com/rVnun.png)
Let $A$ be a closed and bounded subset of $\mathbb{R}$ with the standard (order) topology. Then $A$ is a compact subset of $\mathbb{R}$. - Mathematics Stack Exchange
![Let $A$ be a closed and bounded subset of $\mathbb{R}$ with the standard (order) topology. Then $A$ is a compact subset of $\mathbb{R}$. - Mathematics Stack Exchange Let $A$ be a closed and bounded subset of $\mathbb{R}$ with the standard (order) topology. Then $A$ is a compact subset of $\mathbb{R}$. - Mathematics Stack Exchange](https://i.stack.imgur.com/XimUB.png)
Let $A$ be a closed and bounded subset of $\mathbb{R}$ with the standard (order) topology. Then $A$ is a compact subset of $\mathbb{R}$. - Mathematics Stack Exchange
![SOLVED: 30 points) Give the definition of subset of R' to be compact; of compactness to prove that the interval (0,1] on the real Use the definition line Rl is not compact SOLVED: 30 points) Give the definition of subset of R' to be compact; of compactness to prove that the interval (0,1] on the real Use the definition line Rl is not compact](https://cdn.numerade.com/ask_images/59a9a9b1a9774285a53fb1beaa1325c8.jpg)