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the dimensional formula of∫ tdt is
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![If f(x) = Integration t sin t from 0 to x, then f'(x) is [MCQ]](https://d77da31580fbc8944c00-52b01ccbcfe56047120eec75d9cb2cbd.ssl.cf6.rackcdn.com/b77e0633-a335-40b7-97c9-d886d136e9c6/slide29.jpg "If f(x) = Integration t sin t from 0 to x, then f'(x) is [MCQ]")
If f(x) = Integration t sin t from 0 to x, then f'(x) is [MCQ]
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Let function F be defined as F(x) = int1^xe^t/tdt, x > 0 , then the value of the integral int1^xe^t/t + adt, where a > 0, is :
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If ∫f(t) dt for t ∈ [0,x] = x + ∫t f(t) dt for t ∈ [x,1], then the value of f(1) is ... (a) 1/2 (b) 2 (c) 1 - Sarthaks eConnect | Largest Online Education Community
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